Yesterday’s lesson started out with Blake doing his presentation on the yo-yo and the physics behind it and how it works. We then moved on to a handout that we had gotten about position vs. time graphs. There were three graphs which were all different. They were connected to the previous classes because we have been looking at position vs. time graphs for awhile now and also some of the formulas we have been using such as displacement and velocity.
The first graph we were given the points and had to construct it ourselves. We then had to do the following things with the corresponding graph:
• Describe the motion of the graph by examining the lines on the grid; whether it was a constant positive velocity or not moving.
• We had to find the objects displacement which can be found by taking the ending positing and subtracting it by the initial position.
• We also then examined the graph to find which part of the trip was the fastest.
The second graph was another distance vs. time graph and with this one we had to:
• Find the velocity over each time interval and then find the average velocity over the entire graph. Velocity is equal to distance divided by the time and average velocity is equal to total distance divided by total time.
The last graph that we looked at was a distance vs. time graph which had a curve in it. We had to do the following:
• Find the instantaneous velocity at PT. A where you draw a tangent line so it barely touches the point on the graph. We then find 2 points such as (3,4) and (5,6). We will then find the slope of the graph which is equal to y2-y1 divided by x2-x1.
• The last part we had to find the average velocity of the graph where we had drawn a line straight across point b to point d, found 2 points on the line and found the slope of those points and that had given us the answer.
There was then some textbook questions at the end
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