Thursday, 19 April 2012

Law of Universal Gravitation

We started Thursday's class by finishing correcting assignment six.  We then reviewed Wednesday's class by going over the Law of Universal Gravitation by taking notes on the key points. These notes included the following:

  • The forces of attraction are inversely proportional to the square of the distance between the two objects. I.e. if the distance doubles, the force will be one quarter the original amount.
  • No value of distance would eliminate the force fully.
  • Remember 'g' is an extremely small number. 
Later, we went through examples followed by the assignment #1-4 on page 225.

Ex. 1 Calculate the force of attraction between two bodies that are placed 6.0cm apart and have a mass of 345kg and 430kg respectively.

M1= 345kg               F=G(M1)(M2)           F= 6.67x10^-11  Nm^2 [345kg(430kg)]
M2= 430kg                          d^2                                               Kg^2        0.06m^2
d= 6.0cm ( 0.06m)
F=?                                                                 F= 2.7x10^-3 N


Next is Brady!

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