Today in class we went over part c of the Newtons Third Law example we began the other day. Afterwards we did similar questions on page 149, 1-3a in the text book. Once we were done, we began another assignment due tomorrow, or I guess this present class. We also got our quizzes back.
part c) find the force exerted by toboggan one on toboggan two,
Fnet=ma
=(55 kg)(2.2 m/s squared [E])
=121 N [E]
We take the force of 22 N [W] from b and plug it into another equation to find the total force.
Fnet= Fa + Fa
121= -22 + Fa
Fa= 143 N [E]
Next is Kurtis
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