Example:
A boy pulls his wagon, a mass of 15kg, giving is a horizonal accelleration of 1.0m/s². If the wagons handle makes and angle at 35° with the ground as he is pulling it, there is a frictional force of 3.0 N opposing to the wagons motions, with that what is the force he is pulling the handle of the wagon?
M=15kg
A= 1.0m/s² ( forward)
Ff=3.0 N ( backward)
Fa= ?
Fnet= mass X Acceleration (15.0kg){(1.0m/s² ( forward)}= 15 N Forward... + 3 N= 18 N Forward
Cos35 °= 18 N = 18 N = 22 N ( Forward35°Up)
Fa Cos35°
We then continued on with Newtons Third Law, " To every action there is an equal and opposite reaction." We began our new Lab. We started to get the Labquests ready by calibrating the force sensors. We also got our string and mass. Now we can begin our labs today effeciently.
No comments:
Post a Comment